-3a^2-11a-6=0

Solution for -3a^2-11a-6=0 equation:

-3a^2-11a-6=0

a = -3; b = -11; c = -6;
Δ = b2-4ac
Δ = -112-4·(-3)·(-6)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-7}{2*-3}=\frac{4}{-6}
=-2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+7}{2*-3}=\frac{18}{-6}
=-3
$